#### Answer

Minimum launch speed to complete the jump $=5.56m/s$

#### Work Step by Step

$S=ut+\frac{1}{2}at^{2}$
$4=0+4.9t^{2}$
$t=0.9s$
So, required horizontal speed = $\frac{5}{0.9}m/s=5.56m/s$

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Published by
Pearson

ISBN 10:
0-32160-183-1

ISBN 13:
978-0-32160-183-4

Minimum launch speed to complete the jump $=5.56m/s$

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